(x^2+8x+16)/(x^2-2x-24)

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Solution for (x^2+8x+16)/(x^2-2x-24) equation: 


D( x )

x^2-(2*x)-24 = 0

x^2-(2*x)-24 = 0

x^2-(2*x)-24 = 0

x^2-2*x-24 = 0

x^2-2*x-24 = 0

DELTA = (-2)^2-(-24*1*4)

DELTA = 100

DELTA > 0

x = (100^(1/2)+2)/(1*2) or x = (2-100^(1/2))/(1*2)

x = 6 or x = -4

x in (-oo:-4) U (-4:6) U (6:+oo)

(x^2+8*x+16)/(x^2-(2*x)-24) = 0

(x^2+8*x+16)/(x^2-2*x-24) = 0

x^2+8*x+16 = 0

x^2+8*x+16 = 0

DELTA = 8^2-(1*4*16)

DELTA = 0

x = -8/(1*2)

x = -4 or x = -4

(x+4)^2 = 0

x^2-2*x-24 = 0

x^2-2*x-24 = 0

DELTA = (-2)^2-(-24*1*4)

DELTA = 100

DELTA > 0

x = (100^(1/2)+2)/(1*2) or x = (2-100^(1/2))/(1*2)

x = 6 or x = -4

(x+4)*(x-6) = 0

((x+4)^2)/((x+4)*(x-6)) = 0

x+4 = 0 // - 4

x = -4

x in { -4} 

x belongs to the empty set

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